Sucking The Heat Of The Ocean

avn-l

This infrared imagery shows lots of tropical cyclone activity, sucking heat out of the ocean and radiating it off into space at those bright red spots. This year has record cyclone activity in the north Pacific, which means record amounts of heat being removed from the oceans.

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11 Responses to Sucking The Heat Of The Ocean

  1. Evaporating water absorbs about 950 Btu/lb. Over an hour a pound of evaporating water absorbs 278 Watts (950/3.412). ToA is 340 W/m^2. CO2 RF is 2.0 W/m^2. Water is the heat moving champion of the globe.

    • DD More says:

      Nic, I found this on water and heat.
      So Evaporation of water is 2,500,000 J/kg. http://www.theweatherprediction.com/habyhints2/524/

      And since most of this energy is taken from the nearby sea water – it will cool
      Specific Heat Sea Water = 4,009 J/kg oC 2,500,000/4,009 = 623 or 623 kg by 1- C
      Since there is 1,000 Kg per m^3 or 100 Kg per cm-m^2, 1″ (2.54 cm) of water sublimated will cool the next (623/100)/2.54 = 2.45″ of water 1 oC.

      Oh yea, the average amount of evaporation on open ocean (non-ice) is around 140 cm. That’s how the oceans cool.

      Wiki Pacific Typhoons 1998 & 2015 pages list

      1998 –
      Total depressions 22 official, 5 unofficial
      Total storms 15 official, 3 unofficial
      Typhoons 8 official, 1 unofficial
      Super typhoons 3 unofficial

      2015 – to date
      Total depressions 35
      Total storms 25 official, 1 unofficial
      Typhoons 16
      Super typhoons 8 (unofficial)

      How many inches of water do you think each sq meter of ocean got sucked up by these systems? No wonder the Pacific temperatures are not close to 1998.

      Evaporation from the Surface of the Globe – They peg the total energy for evaporation ocean plus land at 1.26 X 10E24 or 25 pecent of ‘energy in’ at the surface.
      paper here – http://www.eolss.net/sample-chapters/c07/e2-02-03-02.pdf

  2. Stewart Pid says:

    Hey I thought the climate liars said the heat was hiding at the bottom of the ocean … safely out of the cyclones spinning on the surface😉

  3. mkelly says:

    So the cyclones are trying to offset the El Niño?

  4. ntesdorf says:

    I’m sure all this powerful stuff must be hidden somewhere there in the IPCC climate models! It’s just that you can see it there easily.

  5. omanuel says:

    Perhaps ocean heat is like solar neutrinos that oscillate away before being detected. With modern “science,” all things are possible !

    • David A says:

      Oliver, congratulations on NOT playing the same song over and over. In a few days I will have a question for you in your field, just no time now. Thanks

  6. First off, a discussion of units.

    A watt is a metric unit of power, energy over time, not energy per se. The metric energy unit is the joule, English energy unit is the Btu. A watt is 3.412 Btu per English hour or 3.600 kilojoule per metric hour.

    In 24 hours ToA power of 340 W/m^2 will deliver 1.43 E19 Btu to a spherical surface with a radius of 6,386 km. The CO2 RF of 2 W/m^2 will deliver 8.39 E16 Btu, 0.59% of the ToA.
    At 950 Btu/lb of energy, evaporating 0.74 inches of the ocean’s surface would absorb the entire ToA, evaporating 0.0044 inches of the ocean’s surface would absorb the evil unbalancing CO2 RF.

    More clouds. Big deal.

    ToA spherical surface area, m^2 5.125.E+14
    W = 3.412 Btu/h 3.412.E+00
    ToA, 340 W/m^2, Btu/24 h 1.43E+19
    CO2 RF, 2 W/m^2, Btu/24 h 8.39E+16

    Ocean surface , m^2 3.619E+14
    m^2 = 10.764 ft^2 1.076E+01
    Ocean surface, ft^2 3.895E+15
    Water density, lb/ft^3 62.4
    Lb of water in 1 foot of ocean 2.431E+17
    Evaporation, Btu/lb 950.0

    Amount of ocean evaporation
    Feet needed to absorb ToA 0.062
    Inches needed to absorb ToA 0.74
    Feet needed to absorb CO2 RF 0.0004
    Inches needed to absorb CO2 RF 0.0044

    Check ’em Danno.

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